Question 1132749
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If x and y are the dimensions under the question, then from the condition you have these two equations


    2x +  y = 320     yards   (1)
    2x + 2y = 400     yards   (2)


Subtract eq(1) from eq(2). You will get  y = 400-320 = 80 for one dimension  (y).


Then for x you have from eq(1)  2x + 80 = 320  ====>  2x = 320-80 = 240  ====>  x = 240/2 = 120.



<U>ANSWER</U>.  The dimensions are 120 and 80 yards.  80 yards go along the wall.  120 yards go perpendicularly to the wall.
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Solved.