<PRE><B>Question 1132693</B>
Meg rowed her boat upstream at a distance of 48 mi. then rowed back to the starting point. The total time of the trip was 16 hours. If the rate of the current was 4mph, find the average speed of the boat relative to the water 
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Upstream DATA::
dist = 48 mi ; time = t hours ; rate = 48/t mph
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Downstream DATA:
dist = 48 mi ; time = 16-t hrs ; rate = 48/(16-t) mph
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Rate equations:
boat + 4 mph = 48/l6-t)
boat - 4 mph = 48/t
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Solve for &quot;boat&quot;:
2*boat = 48/(16-t) + 48/t
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boat rate in still water =  = 24/(16-t)+ 24/t = [24t+24*16-24t]/[t(16-t)]
= [24*16]/[16t-t^2]
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