Question 1132627
ashley's mother is 58.
her mother is 8 years younger than twice ashley's age.


let a = ashley's age.


the formula for her mother being 8 years younger than twice ashley's age is:


58 = 2a - 8


add 8 to both sides of this equation to get 58 + 8 = 2a
combine like terms to get 66 = 2a
divide both sides of this equation by 2 to get 33 = a


that's ashley's age.


58 = 8 years younger than 2 times 33 which is equal to 8 years younger than 66 which is equal to 58 which is true.


solution is that ashley is 33 years old.