Question 1132594
Use definition of logarithm
:
y = log base b (x), then x = b^y
:
-1/2 = log base x (1/6)
:
1/6 = x^(-1/2)
:
1/6 = 1/x^(1/2)
:
cross multiply the two fractions
:
x^(1/2) = 6
:
square both sides of =
:
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x = 36
:
check answer
:
log base base 36 (1/6) = -1/2
:
-1/2 = -1/2
:
answer checks
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