Question 1132397
P(x>9) includes the last 3, and their sum is 0.21
P(x>=9) includes the last 4, and that sum is 0.41
P(5<x<=10) includes 6-10, or the middle four.  The sum is 0.64
E(X)=sum of 
3(0.08)=0.24
5(0.10)=0.50
7(0.16)=1.12
8(0.25)=2
9(0.20)=1.8
10(0.03)=0.3
12(0.13)=0.156
16(0.05)=0.8
That sum is 6.916