Question 1132454
.
the probability that 3 boys passed an exam are 2/3,5/8,3/4 respectively.
Find the probability that 


<pre>
(a)  all the three boys passed:                             P = {{{(2/3)*(5/8)*(3/4)}}}.



(b)  the probability that none of the three boys  passed:   P = {{{(1-(2/3))*(1-(5/8))*(1-(3/4))}}}.



(c)  the probability that only two boys passed:             P = {{{(2/3)*(5/8)*(1-3/4)}}} + {{{(2/3)*(3/4)*(1-5/8)}}} + {{{(5/8)*(3/4)*(1-2/3)}}}.
</pre>

Solved.