<PRE><B>Question 1132434</B>
there are 201 numbers.
fifty of them (1/4) are divisible by 4

One third of those divisible by 4 are divisible by 6 as well, and two-thirds of 50 is 33

some additional are divisible by 10 and not 6 (40, 80, 100, 140,160,200, 220) leaving 26

the numbers left from 25-100 inclusive are
28/32/44/52/56/64/68/76/88/92 for 10 numbers 
look now at 
104/108/112/116/124/128/132/136/144/148/152/156/164/168/176/188/192/196, and 108, 132,  144, 156, 168, 192 are excluded, so there are 12 left
204/208/212/216/220/224 --exclude 204 and 216 for 4
The total number is 26
probability of choosing one is 26/201 and the second would be 25/200
that joint probability is 0.016

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