Question 1132436
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We need to assume that there is equal probability that the first child is male or female.  After that, the probability is 3/5 that the next child will be the same gender and 2/5 that it will be different.  Then...<br>
(1) all male<br>
P(MMM) = (1/2)(3/5)(3/5) = 9/50<br>
(2) 2 male, 1 female<br>
P(MMF) = (1/2)(3/5)(2/5) = 6/50
P(MFM) = (1/2)(2/5)(2/5) = 4/50
P(FMM) = (1/2)(2/5)(3/5) = 6/50
total 16/50<br>
(3) 1 male, 2 female<br>
P(MFF) = (1/2)(2/5)(3/5) = 6/50
P(FMF) = (1/2)(2/5)(2/5) = 4/50
P(FFM) = (1/2)(3/5)(2/5) = 6/50
total 16/50<br>
(4) all female<br>
P(FFF) = (1/2)(3/5)(3/5) = 9/50<br>
Note that the sum of all the probabilities is 1, giving confidence that the calculations were correct.<br>
You can use the probabilities shown to answer the questions that were asked.