Question 1132427
An isosceles triangle has a vertical angle of 120 degree and a base 40cm.
What will be the length of it's altitude.
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Each "base angle" is 30 degs.
h = altitude
tan(30) = h/(base/2) = h/20 = sqrt(3)/3
h = 20*sqrt(3)/3 cm
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it's = it is