Question 1132367
, . Find the age of each now. 

let Aidan’s age be {{{x}}} and Ethan’s age be {{{y}}}

given:

Aidan is five times as old as Ethan

{{{x=5y}}}......eq.1

but in four years, he will be 8 years more than thrice as him

{{{x+4=3(y+4)}}}......eq.2

substitute {{{x}}} from eq.1

{{{5y+4=3y+12}}}......solve for {{{y}}}

{{{5y-3y=12-4}}}

{{{2y=8}}}

{{{y=4}}}

go to

{{{x=5y}}}......eq.1..substitute {{{y}}}

{{{x=5*4}}}

{{{x=20}}}

=> Aidan is {{{20}}} years old and Ethan is {{{4}}} years old now