Question 1132358
how do you solve x^2-8x=10 using the quadratic formula 
put in the form ax^2 + bx - 10 = 0
:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=1; b=-8; c=-10
{{{x = (-(-8) +- sqrt( (-8^2) -4*1*-10 ))/(2*1) }}}
:
{{{x = (8 +- sqrt( 64 + 40)/(2)) }}}
:
{{{x = (8 +- sqrt( 104))/(2) }}}
:
{{{x = (8 +- 10.2)/(2) }}}
two solutions
{{{ x = 18.2/2}}}
x = 9.1
and
{{{x = -2.2/2}}}
x = -1.1