Question 1132332
first find equation {{{y=mx+b}}} of the line through ({{{-2}}},{{{3}}}) and ({{{-4}}},{{{13}}})

a slope is {{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(13-3)/(-4-(-2))}}}

{{{m=10/(-4+2)}}}

{{{m=10/-2}}}

{{{m=-5}}}


{{{y=-5x+b}}}......plug in one point to find {{{b}}}

{{{13=-5(-4)+b}}}

{{{13=20+b}}}

{{{13-20=b}}}

{{{b=-7}}}

{{{y=-5x-7}}}=>x-intercept is at ({{{0}}},{{{-7}}})

then, set {{{y=0}}} to find x-intercept 

{{{0=-5x-7}}}

{{{5x=-7}}}

{{{x=-7/5}}}

=> x-intercept is at ({{{-7/5}}},{{{0}}})



 {{{drawing ( 600, 600, -15, 15, -15, 15, 
circle(-2,3,.12),circle(-4,13,.12),
locate(-2,3,p(-2,3)),locate(-4,13,p(-4,13)),
locate(0,-7,p(0,-7)),locate(-2,0.5,p(-7/5,0)),

graph( 600, 600, -15, 15, -15, 15, -5x-7)) }}}