Question 1132311
.
<pre>
Let X be the amount invested at 9%.

Then amount invested at 12% is (x+50000) Php.


Your equation, from the condition, is


    <U>interest at 12%</U>  -  <U>interest at 9%</U> = 13500,     or


    0.12*(x+50000)    - 0.09*x         = 13500,


Simplify and find x = {{{(13500-0.12*50000)/(0.12-0.09)}}} = 250000 Php.


<U>Answer</U>.  The amount  of  Php 250000 was invested at 9%.

         The amount of 25000+50000 Php = 300000 Php was invested at 12%.


<U>Check</U>.   0.12*300000 - 0.09*250000 = 13500.     ! Exactly correct !
</pre>

Solved.


-----------------


Making a Table for such simple problem is SPENDING YOUR TIME for nothing.



===============


It is a standard and typical problem on investments.


If you need more details,  &nbsp;or if you want to see other similar problems solved by different methods, &nbsp;look into the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.