Question 1132277
1) i +j = 17
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2) ij = 66
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solve equation 1 for i
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i = 17 -j
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substitute for i in equation 2
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(17 -j)j = 66
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17j -j^2 = 66
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j^2 -17j +66 = 0
:
(j-6)(j-11) = 0
:
j = 6 or j = 11
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use equation 1, then if j=6 then i = 17 -6 = 11 and if j=11 then i = 17 -11 = 6
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the two positive integers are 6 and 11
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