Question 1132275
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<pre>
From the condition, the incomes of A, B and C are 5x, 4x and 3x respectively, where x is the common measure for the three income values.


Similarly, their spendings are 8y, 5y and 4y, respectively, where y is the common measure for the three spending values.


We also are given that


    5x - 8y = 80      (1)     ("A save rupee 80")    and

    5x = 1200.        (2)     ("the income of A is 1200")


From eq(2),  x = {{{1200/5}}} = 240;  then from eq(1)


    y = {{{(5x-80)/8}}} = {{{(5*240-80)/8}}} = 140.



Now saving for B is  4x - 5y = 4*240 - 5*140 = 260.     <U>Answer</U>

    
    saving for B is  3x - 4y = 3*240 - 4*140 = 160.     <U>Answer</U>
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Solved.