Question 1132237
{{{ 2x^3-3x + 1  = Ax(x^2+1)+Bx + C }}}
= {{{ Ax^3 + Ax + Bx + C }}}
= {{{ Ax^3 + (A+B)x + C }}}

By inspection (compare the last line to the left hand side of the first line) you can see C=1, A=2, and then solve A+B=-3 for B=-5<br>

Note that "a" is not necessarily the same as "A"  (be precise)