Question 1132218
If ln a=2, ln b=3, and ln c=5, evaluate the following: 


In square root a^3 b^2 c^1 
<pre>{{{matrix(3,3, ln (a), "=", 2, ln (b), "=", 3, ln (c), "=", 5)}}}
Assuming In square root a^3 b^2 c^1 is ACTUALLY {{{ln(sqrt(a^3b^2c^1))}}}, we get:
{{{ln (sqrt(a^3b^2c))}}} =====> {{{ln (a^3)^(1/2)(b^2)^(1/2)c^(1/2)}}} ======> {{{matrix(2,1, " ", ln (a^(3/2)b^(2/2)c^(1/2)))}}} =====> {{{matrix(2,1, " ", ln (a)^(3/2) + ln (b) + ln (c)^(1/2))}}} =====> {{{(3/2) * ln (a) + ln (b) + (1/2) * ln (c)}}}
Substituting 2 for ln (a), 3 for ln (b), and 5 for ln (c), we get: {{{highlight_green(matrix(1,5, (3/2) * 2 + 3 + (1/2) * 5, "=", 3 + 3 + 5/2, "=", highlight(8&1/2)))}}} <b><==== Correct answer</b>