Question 1132218


If {{{ln(a)=2}}}, {{{ln (b)=3}}}, and {{{ln (c)=5}}}, evaluate the following: 


{{{ln(a)=2}}} =>{{{a = e^2}}}
{{{ln (b)=3}}}=>{{{b = e^3}}}
{{{ln (c)=5}}}=>{{{c = e^5}}}


{{{sqrt(a^3* b^2* c^1)=sqrt((e^2)^3* (e^3)^2* e^5) }}}

{{{sqrt(a^3* b^2* c^1)=sqrt((e^3)^2* (e^3)^2* (e^2)^2*e) }}}

{{{sqrt(a^3* b^2* c^1)=e^3*e^3*e^2*sqrt(e) }}}

{{{sqrt(a^3* b^2* c^1)=e^8*sqrt(e) }}}

approximately:{{{4914.768840}}}