Question 1132202
Four members of one family have a combined age of 135 years.

Jeff is twice as old as his daughter Ann, while Trudy is 5 years younger than her husband, Jeff.

Harry is a third of his mother Trudy's age.

How old are each of the four members of this family?
<pre>Let Ann's age be A
Then Jeff's is 2A, Trudy's is 2A - 5, and Harry's is {{{matrix(1,3, (1/3)(2A - 5), or, (2A - 5)/3)}}}
We then get: {{{matrix(1,3, A + 2A + 2A - 5 + (2A - 5)/3, "=", 135)}}}
{{{matrix(1,3, 5A + (2A - 5)/3, "=", 140)}}}
15A + 2A - 5 = 420 -------- Multiplying by LCD, 3
17A = 425
We then get: {{{highlight_green(matrix(4,6, Ann, is, 425/17, "=", 25, years-old, Jeff, is, 2(25), "=", 50, years-old, Trudy, is, 2(25) - 5, "=", 45, years-old, Harry, is, 45/3, "=", 15, years-old))}}}