Question 1132202
 Four members of one family have a combined age of 135 years.
j + a + t + h = 135 
 Jeff is twice as old as his daughter Ann,
j = 2a
 while Trudy is 5 years younger than her husband, Jeff.
j = t + 5 
 Harry is a third of his mother Trudy's age.
h = {{{1/3}}}t
:
In the 2nd equation replace j with (t+5)
t + 5 = 2a
a = {{{(t+5)/2}}}
:
In the first equation replace in j + a + t + h = 135
j = (t+5)
a = {{{(t+5)/2}}}
h = {{{1/3}}}t
(t+5) + {{{(t+5)/2}}} + t + {{{1/3}}}t = 135 
Multiply by 6 cancel the denominators
6(t+5) + 3(t+5) + 6t + 2t = 6(135)
6t + 30 + 3t + 15 + 6t + 2t = 810
17t + 45 = 810
17t = 810 - 45
17t = 765
t = 45 yrs is Trudy's age
:
 How old are each of the four members of this family? 
j = 45 + 5
j = 50 yrs is Jeff's age
:
a = 50/2
a = 25 is Ann's age
and
h = {{{1/3}}}(45)
h = 15 yrs is Harry's age
:
:
:
check 50 + 45 + 25 + 15 = 135