Question 1132157


 {{{-13=4x-3y }}}.........eq.1
{{{5x+2y=1  }}}.........eq.2........solve for {{{x}}}
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{{{5x+2y=1  }}}.........eq.2
{{{x=-2y/5+1/5  }}}.............substitute in eq.1
 
{{{-13=4(-2y/5+1/5 )-3y}}}

{{{-13=-8y/5+4/5 -3y}}} ...both sides multiply by {{{5}}}

{{{-65=-8y+4-15y }}}

{{{-65=-23y+4}}}

{{{23y=4+65 }}}

{{{23y=69 }}}

{{{y=3 }}}

go to {{{x=-2y/5+1/5  }}}........., substitute {{{y}}}

{{{x=-(2*3)/5+1/5  }}}

{{{x=-6/5+1/5 }}}

{{{x=-5/5 }}}

{{{x=-1}}}

solution:

({{{-1}}},{{{3}}})

{{{ graph( 600, 600, -10, 10, -10, 10, -5x/2+1/2, (4x+13)/3) }}}