Question 1132147
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<pre>
{{{x^12-y^12}}} = {{{(x^6-y^6)*(x^6+y^6)}}} = {{{(x^3-y^3)*(x^3+y^3)*(x^2+y^2)*(x^4-x^2*y^2+y^4)}}} = {{{(x-y)*(x^2+xy+y^2)}}}.{{{(x+y)*(x^2-xy+y^2)}}}.{{{(x^2+y^2)*(x^4-x^2*y^2+y^4)}}}.
</pre>

Completed and solved.