Question 1132133


Solve for {{{0}}}° ≤ {{{theta}}} ≤ {{{360}}}°: 

{{{2cos^2(theta) - 3sin^2(theta) - 2 = 0 }}}

{{{- 2+2cos^2(theta) - 3sin^2(theta)  = 0 }}}

{{{- 2(1-cos^2(theta)) - 3sin^2(theta)  = 0 }}}

{{{- 2sin^2(theta) - 3sin^2(theta)  = 0 }}}

{{{- 5sin^2(theta)  = 0 }}}

{{{sin^2(theta)  = 0 }}}

{{{theta=sin^-1(0)}}}

{{{theta=0}}}° and {{{theta=180}}}°