Question 1132112
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<pre>
Let the ones digit of the number is A; then the tens digit is (11-A).

Hence, the digit itself is  10*(11-A) + A.


Then the digits are reversed in the number, the new number is  10A +(11-A).


The new number and the original number are related each to other by this equation


10A + (11-A) = 2*(10*(11-A) + A) + 7.


We just completed the setup.
We have now one equation for single unknown A.


Simplify and solve for A:


10A + 11 - A = 2*(110 - 10A + A) + 7

9A + 11 = 220 - 18A + 7

9A + 18A = 227 - 11

27A = 216

A = {{{216/27}}} = 8.


<U>ANSWER</U>.  The ones digit is  8.  The tens digit is  11-8 = 3.  The number itself is  38.
</pre>

Solved.


Check it on your own that the solution and the answer are correct.


Good problem.  Hope everything is clear to you.