Question 1132102
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From the given information, we know that two of the roots are -3 and 1/2.<br>
Vieta's Theorem tells us the product of the three roots of a cubic polynomial is (opposite of constant term) divided by (leading coefficient): a/a = 1.<br>
Therefore, the third root is -2/3.<br>
So the polynomial is<br>
{{{(x+3)(2x-1)(3x+2) = 6x^3+19x^2+x-6}}}