Question 1132103
roots are (1/2)(-2+/- sqrt (4p^2-4q))
sqrt(4p^2-4q)=2*sqrt(p^2-q).  2s cancel
roots are -1+sqrt(p^2-q) and -1- sqrt(p^2-q)
the difference is 2sqrt(p^2-q) and that equals 2
so sqrt(p^2-q)=1
p^2-q=1, squaring both sides
p^2=1+q