Question 102786
Every time I try to solve this problem, nothing comes out the same and I can't seem to figure out where my mistake is to determine if any of my solutions are correct. Can someone please show me the correct way to solve this problem?
. Divide:
Assume you mean
{{{(x^2-3x+2)/(x^2-1)}}}
------------
{{{(7x-14)/(7x+7)}}}
:
Let's do the numerator fraction and the denominator fraction separately:
: 
Simplify the numerator fraction:
{{{(x^2-3x + 2)/(x^2-1)}}}
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Note that you can factor both denominator and numerator to:
{{{((x-2)(x-1))/((x+1)(x-1))}}}
:
Note that the (x-1)'s will cancel leaving you with:
{{{((x-2))/((x+1))}}} 
:
:
Simplify the denominator fraction
{{{(7x-14)/(7x+7)}}}
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Note that you can factor out the 7's
{{{(7(x-2))/(7(x+1))}}}
:
7's cancel, leaving you with:
{{{(x-2)/(x+1)}}}
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Put it all back together and you have:
{{{((x-2))/((x+1))}}}
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{{{(x-2)/(x+1)}}}
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Remember you invert the dividing fraction and multiply:
{{{((x-2))/((x+1))}}} * {{{((x+1))/((x-2))}}} = 1
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Note that everything cancels
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