Question 1132057
x^3+4x^2+x-6=0
with synthetic division, using -3
1-----4----1---- -6
1-----1--- -2-----0
(x+3)(x^2+x-2)=0, so -3 is a root 
(x+3)(x+2)(x-1)=0
roots are -3, -2, and +1

(i) is 14

(ii) is 36

(iii) is (-5)(-1)(-2)=-10

{{{graph(300,300,-10,10,-10,10,x^3+4x^2+x-6)}}}