Question 4517
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<pre>
If and when you are given the sum of three consecutive even integers - <U>KNOW and REMEMBER</U>  that the middle number is one third  ( {{{1/3}}} ) of the sum.


In this case, the middle number of the three consecutive even integers is  {{{138/3}}} = 46,


so the greatest of them is  48.     <U>ANSWER</U>
</pre>

Solved.


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This problem was specially invented and designed for you in order you learned this simple truth. 


<pre>
    (n-2) + n + (n+2) = 138  ====>  3n = 138  ===>  n = {{{138/3}}} = 46  ====>  n+2 = 46 + 2 = 48.
</pre>