<PRE><B>Question 1132012</B>
There are (52C13) = 635,013,559,600, where 52C13 = 52!/(13! * (52-13)!) 
:
possible hands, and only 4 of them (spades, hearts, diamonds, clubs) have a single 13-card suit
:
4/635,013,559,600 = 1/158,753,389,900
:
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That’s 1 out of every 158 billion+ hands
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