Question 1131984
<pre>
{{{f(x) = k(x+4^"")(x-5^"")(x-(-3-i)^"")(x-(-3+i)^"")(x-(5+5i)^"")(x-(5-5i)^"")}}}

Substitute 0 for x, and -54 for f(x), get

-54 = k(-10000)

So k = -54/(-10000) which reduces to k = 27/5000

{{{f(x) = expr(27/5000)(x+4^"")(x-5^"")(x-(-3-i)^"")(x-(-3+i)^"")(x-(5+5i)^"")(x-(5-5i)^"")}}}

Multiply that out (big job) and get:

{{{f(x) = (27/5000)x^6 - (27/1000)x^5 - (54/625)x^4 + (189/125)x^3 + (81/50)x^2 - (243/10)x - 54}}}

{{{graph(400,400,-10,10,-100,100, (27/5000)x^6 - (27/1000)x^5 - (54/625)x^4 + (189/125)x^3 + (81/50)x^2 - (243/10)x - 54 )}}}


Edwin</pre>