<PRE><B>Question 1131976</B>
&lt;br&gt;
Note even a very rough sketch of the four given points, without doing any calculations, suggests that the figure might be a parallelogram or even a rectangle, but not a rhombus.&lt;br&gt;
For ABCD to be a rhombus, we must have all three of the following:&lt;br&gt;
(1) AB parallel to CD (slopes the same)
(2) BC parallel to AD (slopes the same)
(3) AC perpendicular to BD (product of slopes is -1)&lt;br&gt;
If any ONE of these is not satisfied, the figure is not a rhombus.&lt;br&gt;
(1) slope of AB: 5/8; slope of CD: 5/8 -- okay
(2) slope of BC: 6/2 = 3; slope of AD: 6/2 = 3 -- okay
(3) slope of AC: 11/6; slope of BD: -1/10 -- NOT okay&lt;br&gt;
The figure is indeed a parallelogram, because opposite pairs of sides are parallel.  But the slopes of the diagonals are not perpendicular.&lt;br&gt;
ANSWER: The figure is not a rhombus, because the diagonals are not perpendicular.</PRE>