Question 1131623
A bus and a car leave a town at 10:30 AM and travel in opposite directions.
 The bus travels at an average speed of 50km/hr and the car travels at the average speed of 55km/hr 
:
Let t equal the time taken for the journey. 
i) Write an expression in t for the distance travelled by bus
50t 
ii) Write an expression in t for the distance travelled by the car
55t
iii) write an equation in t to show the time at which the bus and the car are 140km apart 
50t + 55t = 140
105t = 140
iv) Solve for T
t = 140/105
t = 1{{{1/3}}} hrs which is 1 hr 20 min, 10:30 + 1:20 = 11:50 am
v) If the car and the bus travelled in the same direction, at what time would the car be 30km in front of the bus?? 
55t - 50t = 30
5t = 30
t = 30/5
t = 6 hrs after 10:30 which is 4:30 pm