Question 1131750
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Profit (in thousands) after x months: P(x) = {{{-3x^2+31.5x-60}}}<br>
A graph, showing the profit function (red) and (for part 6) where the profit is 10000 (green)...<br>
{{{graph(400,400,-2,12,-10,30,-3x^2+31.5x-60,10)}}}<br>
Use your graphing calculator....!<br>
(1) graph the function (a good window is -10 to 10 by -10 to 30)
(2) breakeven point(s) -- where the profit function is 0; estimate or use your graphing calculator
(3) initial --> x=0; evaluate the function at x=0.  Since the revenue is initially 0, the initial cost is -P(0). (You could use your graphing calculator to evaluate P(0); but it's easier just to evaluate P(0) by looking at the function)
(4) best time to end: when the profit is maximum (find vertex of the parabola using your calculator)
(5) profit at 1.5. months: estimate, or evaluate P(1.5) using your calculator
(6) graph P(x)=10 (green line on graph) along with the profit function and find where they intersect (estimate or use your graphing calculator)