Question 1131891
Use the vertex form, {{{y=a(x-h)^2+k}}}

{{{y=a(x+3)^2+5}}}

Now use the point to solve for {{{a}}}.

{{{113=a(3+3)^2+5}}}

{{{113-5=a(6)^2}}}

{{{108=36a}}}

{{{a=108/36}}}

{{{a=3}}}


{{{highlight(y=3(x+3)^2+5)}}}


{{{drawing(600,600,-10,10,-10,120,locate(-3,5,V(-3,5)),locate(3,113,p(3,113)), 
 circle(-3,5,0.12),circle(3,113,0.12),grid(1),blue(line(-3,100,-3,-100)),

graph(600,600,-10,10,-10,125,3(x+3)^2+5))}}}