Question 1131839
{{{drawing ( 600, 600, -50, 50, -10, 20,

locate(0.4,-0.3,C),locate(-9,1,alpha),
locate(-14,-0.3,A),locate(-2,1,beta),locate(2,1,gamma),locate(4,5,delta),
locate(11.3,7,B),line(20,12,20,0),line(-14,0,11.3,7),line(0,0,20,12),
graph( 600, 600, -50, 50, -10, 20, 0)) }}} 


{{{tan(gamma)=6/12}}}

{{{gamma=tan^-1(6/12)}}}

{{{gamma=26.57}}}°


{{{tan(alpha)=3/12}}}

{{{alpha=tan^-1(3/12)}}}

{{{alpha=14.04}}}°


{{{beta=180-gamma}}}°

{{{beta=180-26.57}}}°

{{{beta=153.43}}}°



{{{delta=180-(beta+alpha)}}}°

{{{delta=180-(153.43+14.04)}}}°

{{{delta=180-167.47}}}°

{{{delta=12.53}}}°



{{{AB/sin(153.43)=14/sin(12.53)}}}

{{{AB=14sin(153.43)/sin(12.53)}}}

{{{AB=6.26207/0.216951}}}

{{{AB}}}≈{{{28.9ft}}}



{{{BC/sin(14.04)=14/sin(12.53)}}}

{{{BC=14sin(14.04)/sin(12.53)}}}

{{{BC=3.39639/0.216951}}}

{{{BC}}}≈{{{ 15.7ft}}}