Question 1131812
A normal distribution has a mean of 224 and a standard deviation of 12. Find the probability that a score is in the interval given. (Round your answer to four decimal places.) 
Between 205 and 250 
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z(205) = (205-224)/12 = -19/12
z(250) = (250-224)/12 = 26/12
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P(205< x < 250) = P(-19/12 < z < 26/12) = normalcdf(-19/12,26/12) = 0.9282
Cheers,
Stan H.
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