Question 1131837
helicopter flies from the airport on a course with a bearing of 19degrees.
 After flying for 105 ​miles, the helicopter flies due east for some time.
 The helicopter flies back to the airport with a bearing of 223degrees.
 How far did the helicopter fly on the final leg of its​ journey?
:
Draw this out and find the interior angles of the triangle formed by the course of the helicopter, starts at C, 105 mi to A
A: 19 + 90 = 109 degrees
B: 270-223 = 47 degrees
C: 108 - 109 - 47 = 24 degrees
:
a = final leg distance
b = 105 mi
:
Use the law of sines to find a
{{{a/sin(109)}}} = {{{105/sin(47)}}}
:
a = {{{(sin(109)*105)/(sin(47))}}}
a = 135.7 mi