Question 102926
if
{{{ length= a}}}
{{{width = b}}}
Perimeter = {{{P}}} = {{{34 in}}}

Since  {{{P = 2(a + b)}}}

and {{{a}}} is {{{2 in}}} more than {{{twice}}} its {{{width}}}, we can write 

{{{a = 2*b + 2 in}}}

Then:
{{{P = 2(2*b + 2 in + b)}}}
Or
{{{34 in = 4b + 2b + 4 in}}}
{{{34 in – 4 in = 6b}}}
{{{6b = 30 in}}}
{{{b = 30/6 in}}}
{{{b = 5 in}}}          => {{{a = 2*(10 in + 2 in)= 12 in}}}

check:
{{{P = 2(12 in + 5 in ) }}}
{{{P = 2*17 in }}} 
{{{P = 34 in }}}