Question 1131794

IF you have this:

{{{log(x,log( 2,32))=2 }}}....-> {{{log( 2,32)=log( 2,2^5)=5}}}

{{{log(x,5)=2 }}}........convert to base {{{10}}}

{{{log(5)/log(x)=2 }}}

{{{log(5)=2log(x) }}}

{{{log(5)=log(x^2) }}}=>

{{{5=x^2}}}

{{{x=sqrt(5)}}}