Question 1131797


the point-slope form of the equation of the line:

{{{y-y[1]=m(x-x[1])}}}


 if line passes through: ({{{-3}}}, {{{3}}}), we have 

{{{y-3=m(x-(-3))}}}

{{{y-3=m(x+3)}}}

we need a slope

if line is parallel to {{{y = -(8/3)x - 4}}}, it will have same slope which is {{{-(8/3)}}}

so, your line will be:

{{{y-3=-(8/3)(x+3)}}}

{{{y-3=-(8/3)x-(8/3)3}}}

{{{y-3=-(8/3)x-8}}}

{{{y=-(8/3)x-8+3}}}

{{{y=-(8/3)x-5}}}



{{{drawing ( 600, 600, -10, 10, -10, 10,
circle(-3,3,.12), locate(-3,3,p(-3,3)),
graph( 600, 600, -10, 10, -10, 10, -(8/3)x - 4, -(8/3)x-5)) }}}