Question 1131759

ΔABC, m∠ C = 90º
       m∠B = 30º
  

then,m∠ A = 60º

    
CM- angle bisector,  C = 90º id divided into two  45º angles MCA and MCB, and ΔABC into two Δ (ACM and BCM)

since ∠{{{AMC }}} is in Δ {{{ACM}}}, and we know two other angles, then

    m∠{{{AMC =180-(30+45)=180-75=105}}} º