Question 1131755
In Triangle ABC, AC=19 BC=12 <BAC =32deg Find the possible lengths of AB

So far I calculated option 1 being

 ANGLES      SIDES

<A 32deg      AB 23

<B 57deg      BC 12

<C 91deg      CA 19


I calc this using sin law, I know that I need to use Cosine law but I get stuck
can you please help me
===============
There's no requirement to use the Cosine law.
Why do you think your results are not correct?