Question 102904
The length of a rectangular garden is 1 ft more than 2 times its width.  If the perimeter of the garden is 44 ft, find both dimensions of the garden.

Let the  width of the garden  w = x

The length of the garden  l = 2x+1

 peimeter  of a rectangle = 2(l+w)

 2(l+w) = 44

2(x+2x+1) = 44

(x+2x+1) = 44/2

3x+1= 22

3x+1-1=22-1

3x = 21

3x/3= 21/3

x = 7ft

l = x = 7 ft

w = 2x+1

w = 2(7) +1

w = 15 ft

length = 7 ft and width = 15 ft  is the solution