Question 102907
Please help
{{{(1/2)x-5y=19}}}---------(1)
{{{x-2y=-10}}}-------------(2)

 x- 2y = -10

==> x =-10+2y

sustitute the valve of x in (1)

(1/2(-10+2y))-5y = 19

==> - 5+y -5y = 19

==> -5-4y = 19

==> -4y  = 19+5

==> -4y  = 24

==> -4y/-4 = 24/-4

==>  y = -6

now  x  = -10+2y

pluggin the value of y = -6 

==> x =  -10+2(-6)

==>  x = -10-12
 
==>  x = -22

==>  x = -22 and y = -6 is the solution