Question 1131704
6x^4 - 35x^3 + 62x^2 - 35x + 6 = 0
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check for the factors of 6(this is the constant and also the leading coefficient  in the above equation)
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use the Rational Zeros Theorem 
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factors for 6 are 1, 2, 3, 6
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the possible zeros are
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(+ or - 1, 2, 3, 6)/(1, 2, 3, 6) = + or - 1, 2, 3, 6, 1/2, 1, 3/2, 3, 1/3, 2/3, 1, 2, 1/6, 1/3, 1/2, 1  =
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-6, -3, -2, -3/2, -1, -1/2, -2/3, -1/3, -1/6, 1/6, 1/3, 2/3, 1/2, 1, 3/2, 2, 3, 6 
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look at the graph to see if we can eliminate any of the possible zeros
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{{{ graph( 300, 200, -1, 4, -10, 50, 6x^4 - 35x^3 + 62x^2 - 35x + 6) }}}
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from the graph we see that there are no negative roots and 4 positive roots
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we can eliminate 1/6, 2/3, 1, 3/2, 6
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the roots are 1/3, 1/2, 2, 3
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to check this substitute for x in the equation
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