Question 1131508
write an equation for the line perpendicular to y = 3x - 5 that contains (-2,-3). 
the relationship of the slopes of perpendicular lines m1 * m2 = -1
In this case m1 = 3, find the slope of the perpendicular line
3m = -1
m = {{{-1/3}}}
:
Using the point slope form y - y1 = m(x-x1),
 x1=-2; y1=-3; m={{{-1/3}}}
y -(-3) = {{{-1/3}}}(x -(-2))
minus a minus is a plus
y + 3 = {{{-1/3}}}(x + 2)
y + 3 = {{{-1/3}}}x - {{{2/3}}}
y = {{{-1/3}}}x - {{{2/3}}} - 3
y = {{{-1/3}}}x - {{{2/3}}} - {{{9/3}}}
y = {{{-1/3}}}x - {{{11/3}}} is the equation
: 
looks like this
{{{ graph( 300, 300, -10, 10, -10, 10, 3x-5, (-1/3)x-(11/3)) }}} 
note the green intersects at -2,-3