Question 1131509
The perimeter of a right triangle is 42 and the sum of the squares of its sides is 722. Determine the area of the right triangle.
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a + b + c = 42
a^2 + b^2 = c^2
a^2 + b^2 + c^2 = 722
2c^2 = 722
c = 19
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a^2 + b^2 = 361
a + b = 23
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a^2 - 23a + 84 = 0
a*b = 84
Area = 42