Question 1131433
using inverse matrix:

{{{3x - 2y = 5}}}
{{{x + y = 0}}}


{{{A=matrix(2,2,3,-2,1,1)}}}


and 


{{{B=matrix(2,1,5,0)}}}



{{{A }}}is invertible and 


{{{A^-1}}}={{{(1/5)}}}{{{(matrix(2,2,1,2,-1,3))}}}


Then you get 


{{{X=A^1*B }}}={{{(1/5)}}}{{{(matrix(2,2,1,2,-1,3))}}}*{{{(matrix(2,1,5,0))}}}


= {{{(matrix(2,1, 1, -1))}}}


solutions:

{{{x= 1}}}
{{{y=-1}}}