Question 1131439
break it apart 
sqrt(32)=sqrt(2)(sqrt(16))=4 sqrt(2)
every 2 in an exponent under the radical (if square root) may be removed and become the variable to the first power.  sqrt(k^7) becomes k^3*sqrt(k), the remainder left behind.
sqrt(q^8)=q^4.
multiply everything together to get 4*k^3*q^4*sqrt(2k), noting how the two radical terms are just combined under one radical

do the same for cube roots
cube root of -64 is -4
for cube root of a^8, pull THREE a's out and make it the variable to the first power.
cube root of a^8=a^2*cube root (a^2), the remainder is 2.
This is -4a^2 cube root (a^2)